Question

Алгебраические дроби

Answer 1

$1)\frac{52(t-7)}{t}*\frac{t}{13(t-7)}=\frac{13*4*(t-7)*t}{t*13*(t-7)}=4\\\\2)\frac{48x}{c}:\frac{4x}{c}=\frac{48x}{c}*\frac{c}{4x}=\frac{48}{4}=12\\\\3)(\frac{3z}{4})^{4} =\frac{81z^{4}}{256}\\\\4)\frac{3d^{2}}{d^{2}-4 }:\frac{3d}{d+2}=\frac{3d^{2}}{(d+2)(d-2)}*\frac{d+2}{3d}=\frac{d}{d-2}\\\\5)\frac{a-d}{5q-q^{2}} *\frac{40q-8q^{2}}{d-a}=\frac{a-d}{q(5-q)}*\frac{8q(5-q)}{d-a}=-8\\\\Otvet:\boxed{-8}$

Answer 2

Ответ:

1.    4

2.   12

3.   81*z^4/64

4.   d/(d-2)

5.   -8

Объяснение: сокращаем подобные