Question

помогите с математикой ​

Answer 1

Ответ:

1) $log8+lg125= log_{10}1000 = log_{10x^{3} } = 3$

2) $log_{2}6 - log_{2} \frac{6}{32} = log_{2} (\frac{6}{6}/32) = log_{2} 32 + log_{2} (32) = log_{2^{5} }$

3) $log_{3} 5 - log_{3} 135 = log_{3} 3x^{-3} = -3$

4) $2log_{2} 7 - log_{2} 49 = 2log_{2} 7 - log_{2} 7^{2} = 2log_{2} 7 = 2log_{2} 7 - 2log_{2} 7 = 0$

5) $log_{9} 3 + log_{3^{2} } 3^{3} = \frac{1}{2} + \frac{3}{2} = 2$