Question

Помогите по братски.​

Answer 1

$0,125m^2n^3 -0,25mn+0,625m^2n = \dfrac{1}{8}m^2n^3-\dfrac{1}{4}mn+\dfrac{5}{8}m^2n= \\= \dfrac{1}{8}mn(mn^2-2+5m)$

$328t^2k^3+82t^2k^2 = 82k^2t^2(4k+1)$

$0,09m^6n^5+0,27m^3n^8 - 0,09m^3n^5 = \dfrac{9}{100} m^6n^5+\dfrac{27}{100}m^3n^8-\dfrac{9}{100}m^3n^5 = \\\\=\dfrac{9}{100}m^3n^5(m^3+3n^3-1)$

$1,6t^{11} k^4-3,2t^{10}k+0,8t^9k = \dfrac{8}{5}t^{11}k^4-\dfrac{16}{5}t^{10}k+\dfrac{4}{5}t^9k = \dfrac{4}{5}kt^9(2t^2k^3-4t+1)$

$14m^4-49m^2nk+7m^2n = 7m^2(2m^2-7kn+n)$

$-8t^8k^3y+64t^3k^8 -4t^3k^3 = -4k^3t^3(2t^5y-16k^5+1)$