Question

срочно решите помогите умоляю Господи

Answer 1

$1)\sqrt{25a^{2}}-\sqrt[3]{64a^{3}}-\sqrt[4]{16a^{4}}-\sqrt[6]{676}=\sqrt{(5a)^{2}}-\sqrt[3]{(4a)^{3}}-\sqrt[4]{(2a)^{4}}-\sqrt[6]{26^{2}}=\\\\=5a-4a-2a-\sqrt[3]{26}=-a-\sqrt[3]{26}\\\\a=\sqrt[3]{26}-3\\\\-a-\sqrt[3]{26}=-(\sqrt[3]{26}-3)-\sqrt[3]{26}=-\sqrt[3]{26}+3-\sqrt[3]{26}=3\\\\Otvet:\boxed{3}$

$2)\sqrt[5]{128x^{2}}=24+\sqrt[5]{64x}\\\\\sqrt[5]{(2^{7})*x^{2}}=24+\sqrt[5]{2^{6}x}\\\\2\sqrt[5]{4x}-2\sqrt[5]{2x}-24=0\\\\\sqrt[5]{2x}=m\\\\2m^{2}-2m-24=0\\\\m^{2}-m-12=0\\\\m_{1}=4\\\\m_{2} =-3$

$1)\sqrt[5]{2x}=4\\\\2x=1024\\\\x_{1}=512\\\\2)\sqrt[5]{2x} =-3\\\\2x=-243\\\\x_{2}=-121,5\\\\Otvet:\boxed{512;-121,5}$