Question

СРОЧНО!
АЛГЕБРА 8 КЛАСС
15 БАЛЛОВ

Answer 1

Ответ:

$a) \;\;\frac{22p^4q^2}{99p^5q}=\frac{2q}{9p} \\\\b) \;\;\frac{7a}{a^2+5a} = \frac{7a}{a(a+5)}=\frac{7}{a+5} \\\\c)\;\;\frac{x^2-y&2}{4x+4y}=\frac{(x+y)(x-y)}{4(x+y)}=\frac{x-y}{4}$

$a)\;\;\frac{y-20}{4y}+\frac{5y-2}{y^2}=\frac{y^2-20y+20y-8}{4y^2}=\frac{y^2-8}{4y^2}\\ \\b)\;\;\frac{1}{5c-d}-\frac{1}{5c+d}=\frac{5c+d-5c+d}{(5c+d)(5c-d)}=\frac{2d}{(5c+d)(5c-d)} \\\\c)\frac{7}{a+5}-\frac{7a-3}{a^2+5a}=\frac{7a-7a+3}{a(a+5)}=\frac{3}{a(a+5)}$

$\frac{14*(0.5)^2+14}{7*0.5}-2*0.5 =\frac{3.5+14}{3.5}-1=\frac{175}{35}-1=5-1=4$