Question

above the
An object released from rest from high
ground reaches the ground with
32 m/s speed find initial
height of the

Answer 1

Ответ:

Объяснение:

V= V₀+g*t    V-speed  g-acceleration of gravity ≈ 10 m/s²   t-time

V₀=0 m/s

t=v/g=32/10=3,2 s

h=V²/2g

h=32*32/10*2

h=1024/20

h= 51,2m