Question

Найдите наименьшее целое решение неравенства:
1) х – 4 < 3х + 9;
2) 18х2 - (3х - 2)(6х + 5) < 20;
3) (2x – 3)2 + (3 – 4x)(х + 5) > 82;
4) (x-3)(х + 3) > 2(x - 2)2 – х(х+1).​

Answer 1

Ответ:

$1)1.5 \times 6 {}^{2} - 2 {}^{3} = 1.5 \times 36 - 8 = 54 - 8 = 46 \\ 2) \times - 4 < 3 x + 9 = x - 3x < 9 + 4 = - 2x < 13 = x > - \frac{13}{2} \\ 3)18x { }^{2} - (3x - 2) \times (6x + 5) < 20 = 18x {}^{2} - (18x {}^{2} + 15x - 12x - 10) < = 18x {}^{2} - (18x {}^{2} + 3x - 10) < 20 = 18x {}^{2} - 18x {}^{2} - 3x + 10 < 20 = - 3x + 10 < 20 = - 3x + 10 < 20 = 3x + 10 < 20 = - 3x + 1020 = - 3x + 10 < 20 = - 3x - 20 - 10 = - 3x < 10 = x > - \frac{10}{3} \\ 4)(2x - 3)2 + (3 - 4x) \times (x + 5) < 82 = 4x - 6 + 3x + 15 - 4x {}^{2} - 20x > 82 = - 13x + 9 - 4x {}^{2} > 82 = - 13x + 9 - 4x {}^{2} - 82 > 0 = - 13x + 9 - 4x {}^{2} - 82 > 0 = - 13x - 73 - 4x {}^{2} > 0 = - 4x {}^{2} - 13x - 73 > 0 = 4x {}^{2} - 13x - 73 = 0 = xcr = - 4x {}^{2} - 13x - 73 = 0 = xer = - 4x {}^{2} - 13x - 73 > 0.a = - 4 = xe0$

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