Question

помогите, срочно алгебра ​

Answer 1

2)

$(51,8+44,3+48,2-24,3)*\frac{1}{3} =(51,8+48,2+44,3-24,3)*\frac{1}{3} =(100+20)*\frac{1}{3} =\\\\=\frac{120}{3} =40$

4)

$-11,401-23,17+4,401-10,83=-11,401+4,401-23,17-10,83=-7-34=\\\\=-41$