Question

5) (√m+√2)$^{2}$
6)(√3−√6)$^{2}$
7) (6−√2)$^{2}$

Answer 1

Ответ:

$(\sqrt{m} + \sqrt{2})^{2} ==> m + 2\sqrt{2m} + 2;\\ (\sqrt{3} - \sqrt{6})^{2} ==> 3 - 2\sqrt{18} + 6 = 9 - 2\sqrt{9*2} = 9 - 6\sqrt{2}\\(6 - \sqrt{2})^{2} = 36 - 12\sqrt{2} + 2 = 38 - 12\sqrt{2}$

Объяснение: