Question

Найдите
$tg( \beta )$
если
$\cos( \beta )$
равен
$- 0.28$
​

Answer 1

Ответ:

$-6\frac{6}{7}$

или

$6\frac{6}{7}$

Пошаговое объяснение:

$\sin \beta = \pm \sqrt{1-(\cos \beta)^2} \\\sin \beta = \pm \sqrt{1-(-0.28)^2}= \pm \sqrt{1-0.0784} = \pm \sqrt{0.9216} = \pm 0.96$

1.

$\sin \beta = 0.96\\tg \beta = \frac{0.96}{-0.28} = -\frac{48}{7} = -6 \frac{6}{7}$

2.

$\sin \beta = -0.96\\tg \beta = \frac{-0.96}{-0.28} = \frac{48}{7} = 6 \frac{6}{7}$