Предмет: Геометрия, автор: Tutushaaa

найдите наименьший угол треугольника ABC со сторонами a=45 ,b=70,c=95.

Ответы

Автор ответа: Аноним

cos a=(b^2+c^2-a^2)/2*b*c=(70^2+95^2-45^2)/2*70*95= приблизительно 27градусов

P.S Помог? ставь лучший ответ

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