Предмет: Химия, автор: barbariskaka

Сколько процентов серебра в нитрате серебра AgNO3?

Ответы

Автор ответа: Frankfurt0

Ответ:

m(Ag) = 108 Атомная масса серебра

Mr(AgNO3) = 108 + 14 + 16*3 = 170 Молекулярная масса соли

W(Ag) = m(Ag) / Mr(AgNO3) = 63.5%

Frankfurt0: И точнее не проценты, а массовая доля серебра

barbariskaka: Спасибо чел здравия всему твоему клану

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