Question

Решить уравнение x^3-4x^2-7x+28=0

Answer 1

$x^3-4x^2-7x+28=0\x^2(x-4)-7(x-4)=0\(x-4)(x^2-7)=0\x-4=0\x_1=4;\\x^2-7=0\x_2,_3=pmsqrt7$