Question

погомите пожалуйста..

Answer 1

Объяснение:

1)$\frac{1}{3-2\sqrt{5} }- \frac{1}{3+2\sqrt{5} }=\frac{(3+2\sqrt{5})-(3-2\sqrt{5})}{(3-2\sqrt{5})(3+2\sqrt{5})}=\frac{4\sqrt{5}}{9-20}=-\frac{4\sqrt{5}}{11}$

2)$\frac{1}{5\sqrt{3}-4}-\frac{1}{5\sqrt{3}+4}=\frac{(5\sqrt{3}+4)-(5\sqrt{3}-4)}{(5\sqrt{3}-4)(5\sqrt{3}+4)}=\frac{8}{75-16}=\frac{8}{59}$

Answer 2

$1)\frac{1}{3-2\sqrt{5}}-\frac{1}{3+2\sqrt{5}}=\frac{3+2\sqrt{5}-3+2\sqrt{5}}{(3-2\sqrt{5})(3+2\sqrt{5})}=\frac{4\sqrt{5}}{3^{2}-(2\sqrt{5})^{2}} =\frac{4\sqrt{5}}{9-20}=-\frac{4\sqrt{5}}{11} \\\\\\2)\frac{1}{5\sqrt{3}-4}-\frac{1}{5\sqrt{3}+4}=\frac{5\sqrt{3}+4-5\sqrt{3}+4}{(5\sqrt{3}-4)(5\sqrt{3}+4)}=\frac{8}{(5\sqrt{3})^{2}-4^{2}} =\frac{8}{75-16}=\frac{8}{59}$