Question

Решите уравнение пожалуйста)))

$\frac{2x^2-2}{x+1} = 0$

Answer 1

$\frac{ {2x}^{2} - 2 }{x + 1} = 0 \\ \frac{2( {x - 2)}^{2} }{x + 1} = 0 \\ \frac{2(x - 1)(x + 1)}{x + 1} = 0 \\ 2(x - 1) = 0 \\ 2x - 2 = 0 \\ 2x = 2 \\ x = 1$