Question

Помогите срочно. Даю 20 баллов

Answer 1

Ответ:

1.

$1) \sqrt{48} = 4 \sqrt{3} \\ 2)0.01 \sqrt{1000} = 0.01 \times 10 \sqrt{10} = 0.1 \sqrt{10}$

2.

$1)2 \sqrt{3a} = \sqrt{3a \times 4} = \sqrt{12a} \\ 2) - 5 \sqrt{0.1a} = - \sqrt{0.1a \times 25} = - \sqrt{2.5a}$

3.

$1) \sqrt{36a} - \sqrt{81a} + \sqrt{49a} = 6 \sqrt{a} - 9 \sqrt{a} + 7 \sqrt{a} = 4 \sqrt{a} \\ 2)(2 \sqrt{3} - 3 \sqrt{5}) \sqrt{3} + 4 \sqrt{15} = 2 \sqrt{3} \times \sqrt{3} - 3 \sqrt{5} \times \sqrt{3} + 4 \sqrt{15} = 6 - 3 \sqrt{15} + 4 \sqrt{15} = 6 + \sqrt{15} \\ 3)( \sqrt{13} - 4)( \sqrt{13} + 4) = { \sqrt{13} }^{2} - {4}^{2} = 13 - 16 = - 3 \\ 4)(2 \sqrt{3} - 1) + 2 \sqrt{12} = \sqrt{3 \times 4} - 1 + 2 \sqrt{12} = \sqrt{12} -1 + 2 \sqrt{12} = 3 \sqrt{12} - 1$

4.

$1) \frac{2}{ \sqrt{3} } = \frac{2 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } = \frac{2 \sqrt{3} }{3} \\ 2) \frac{2}{ \sqrt{3} - 1 } = \frac{2 \times ( \sqrt{3} + 1) }{( \sqrt{3} - 1)( \sqrt{3} + 1) } = \frac{2 \sqrt{3} + 2 }{ { \sqrt{3} }^{2} - {1}^{2} } = \frac{2 \sqrt{3} + 2}{3 - 1} = \frac{2( \sqrt{3 + 1)} }{2} = \sqrt{3} + 1$