Question

Помогите пожалуйста!!!!!! Дам 20б!!!! Очень прошу!!! ​

Answer 1

Ответ:

1.      $4 -0.3\sqrt[3]{0.3}$

2.     -0.15

3.      0.8

4.      1

1.       $x \cdot \sqrt{x}$

Пошаговое объяснение:

1.

$\sqrt[3]{-0.0081} = - \sqrt[3]{0.3^4} = -0.3\sqrt[3]{0.3} \\4^0.7 = 2^{1.4}\\2^{1.4}:2^{-0.6} = 2^{1.4-(-0.6)} = 2^{1.4+0.6} = 2^2 = 4\\\sqrt[3]{-0.0081} - 4^0.7:2^{-0.6} = 4 -0.3\sqrt[3]{0.3}$

2.

$\sqrt[6]{\frac{64}{100000000} } \cdot \sqrt[4]{39\frac{1}{16} } : \sqrt[3]{-3\frac{19}{27} } = \\\sqrt[6]{\frac{2^6}{10^8} } \cdot \sqrt[4]{\frac{625}{16} } : \sqrt[3]{-\frac{100}{27} } = \\\frac{2}{10} \sqrt[6]{\frac{1}{10^2} } \cdot \sqrt[4]{\frac{5^4}{2^4} } : \sqrt[3]{-\frac{10^2}{3^3} } = \\-\frac{2}{10} \sqrt[3]{\frac{1}{10} } \cdot \frac{5}{2} \cdot 3\sqrt[3]{\frac{1}{10^2} } = \\-\frac{2\cdot 5 \cdot 3}{10 \cdot 2} \sqrt[3]{\frac{1}{10} } \cdot \sqrt[3]{\frac{1}{10^2} } =$

$=-1.5 \cdot \sqrt[3]{\frac{1}{10^3} } = -1.5 \cdot \frac{1}{10 } = -0.15$

3.

$\sqrt[3]{100} \cdot (\sqrt{2} )^\frac{8}{3} \cdot (\frac{1}{5} )^\frac{5}{3} = \\\sqrt[3]{100} \cdot \sqrt[3 \cdot 2]{2^ 8} \cdot \sqrt[3]{\frac{1}{5^5}} =\\\sqrt[3]{100} \cdot \sqrt[3]{2^4} \cdot \sqrt[3]{\frac{1}{5^5}} =\\\sqrt[3]{\frac{100 \cdot 2^4}{5^5}} = \\\sqrt[3]{\frac{2^2 \cdot 5^2 \cdot 2^4}{5^5}} = \\\sqrt[3]{\frac{2^6 \cdot 5^2}{5^5}} = \\\sqrt[3]{\frac{2^6}{5^3}} = \\\frac{2^2}{5} = \frac{4}{5} = 0.8$

4.

$\sqrt[5]{1\frac{11}{16} \cdot 4.5 } - \frac{\sqrt[5]{9} }{\sqrt[5]{288} } = \\\sqrt[5]{\frac{27}{16} \cdot \frac{9}{2} } - \sqrt[5]{ \frac{9 }{288 }} =\\ \sqrt[5]{\frac{3^3}{2^4} \cdot \frac{3^2}{2^1} } - \sqrt[5]{ \frac{3^2}{3^2 \cdot 2^5 }} =\\ \sqrt[5]{\frac{3^3 \cdot 3^2}{2^4 \cdot 2^1} } - \sqrt[5]{ \frac{1}{2^5 }} =\\ \sqrt[5]{\frac{3^5}{2^5}} - \sqrt[5]{ \frac{1}{2^5 }} =\\\frac{3}{2}- \frac{1}{2} = \frac{2}{2} = 1$

1.

$x^\frac{1}{2} \cdot \sqrt{x} \cdot (x)^\frac{1}{2} = x^\frac{1}{2} \cdot x^\frac{1}{2} \cdot x^\frac{1}{2} \cdot = x^\frac{1+1+1}{2} = x^\frac{3}{2} = x \cdot \sqrt{x}$