Question

Решите уравнение: 2 sin x+1= 0​

Answer 1

$2 \sin(x) + 1 = 0 \\ \sin(x) = - \frac{1}{2} \\ x = ( - 1) {}^{n} \arcsin( - \frac{1}{2} ) + \pi n \\x = ( - 1) {}^{n} ( - 1) \arcsin( \frac{1}{2} ) + \pi n \\ x = ( - 1) {}^{n + 1} \frac{\pi}{6} + \pi n, \: n \in Z$