Question

Алгебра Срочно 50 баллов

Answer 1

$\frac{x^{2}-8x}{x^{3}-8x^{2}+5x-40}=\frac{x^{2}-8x}{(x^{3}-8x^{2})+(5x-40)}=\frac{x(x-8)}{x^{2}(x-8)+5(x-8)}=\frac{x(x-8)}{(x-8)(x^{2}+5)}=\frac{x}{x^{2}+5}\\\\Otvet:\boxed{\frac{x}{x^{2}+5}}$

Answer 2

$\dfrac{x^2-8x}{x^3-8x^2+5x-40}=\dfrac{x\, (x-8)}{x^2(x-8)+5(x-8)}=\dfrac{x\, (x-8)}{(x-8)(x^2+5)}=\dfrac{x}{x^2+5}$