Question

самостоятельная работа #6​

Answer 1

Пошаговое объяснение:

1)

$\frac{5}{6x {y}^{2} } \times \frac{1}{3 {x}^{3} } = \frac{5}{6x {y}^{2} \times 3 {x}^{3} } = \frac{5}{18 {x}^{4} {y}^{2} }$

2)

$\frac{4y \times (2x - y)}{(x + 3y) \times (2x - y)} = \frac{8xy - 4 {y}^{2} }{(x + 3y) \times (2x - y)}$

$\frac{3x \times (x + 3y)}{(x + 3y) \times (2x - y)} = \frac{3 {x}^{2} \times 9xy}{(x + 3y) \times (2x - y)}$

3)

$\frac{2x}{2x - y} = \frac{2x}{(2x - y) (2x - y)(2x + y)} \\ \frac{1}{4 {x}^{2} - {y}^{2} } = \frac{1}{(2x - y)(2x + y)} = \frac{1}{(2x - y)(2x + y)(2x - y)} \\ \frac{3}{4 {x}^{2} - 4xy + {y}^{2} } = \frac{3}{ {(2x - y)}^{2} } = \frac{3}{ {(2x - y)}^{2} \times (2x + y)}$