Question

вынесите множитель под знак корня

Answer 1

$4\sqrt{5}=\sqrt{4^2\cdot 5}=\sqrt{16\cdot 5}=\sqrt{80}\\\\-3\sqrt{a}=-\sqrt{9\cdot a}\\\\9\sqrt{2}=\sqrt{81\cdot 2}=\sqrt{162}\\\\-2\sqrt{b}=-\sqrt{4b}\\\\3\sqrt{5a}=\sqrt{9\cdot 5a}=\sqrt{45a}\\\\\-10\sqrt{0,2b}=-\sqrt{100\cdot 0,2b}=-\sqrt{20b}\\\\5\sqrt{2a}=\sqrt{25\cdot 2a}=\sqrt{50a}\\\\-20\sqrt{0,1\, b}=-\sqrt{400\cdot 0,1\, b}=-\sqrt{40\, b}\\\\-\dfrac{1}{3}\cdot \sqrt{6x}=-\sqrt{\dfrac{6x}{9}}=-\sqrt{\dfrac{2x}{3} }$

$a\sqrt{\dfrac{1}{a} }=\sqrt{\dfrac{a^2}{a} }=\sqrt{a}\\\\-\dfrac{1}{5}\cdot \sqrt{10x}=-\sqrt{\dfrac{10x}{25} }=-\sqrt{\dfrac{2x}{5} }\\\\\dfrac{1}{a}\cdot \sqrt{2a}=\sqrt{\dfrac{2a}{a^2} }=\sqrt{\dfrac{2}{a} }$