Question

дам 20 б пж быстрее​

Answer 1

$1) {x}^{14} \div {x}^{9} \times {x}^{5} = {x}^{14 - 9 + 5} = {x}^{10} \\ 2) {x}^{22} \times ( {x}^{18} \div {x}^{9} ) = {x}^{31} \\ 3)( {x}^{3} {)}^{7} \div ( {x}^{3} {)}^{6} = {x}^{21} \div {x}^{18} = {x}^{3}$