Question

(16а²-1/25b²):(4a-1/5b)
если а=-3/4 b=-1/20
Помогите

Answer 1

$\frac{16a^{2} -\frac{1}{25}b^{2}}{4a-\frac{1}{5}b}=\frac{(4a)^{2}-(\frac{1}{5}b)^{2}}{4a-\frac{1}{5}b}=\frac{(4a-\frac{1}{5}b)(4a+\frac{1}{5}b)}{4a-\frac{1}{5}b}=4a+\frac{1}{5}b\\\\a=-\frac{3}{4} ;b=-\frac{1}{20}\\\\4a+\frac{1}{5} b=4*(-\frac{3}{4})+\frac{1}{5}*(-\frac{1}{20})=-3-\frac{1}{100}=-3-0,01=-3,01\\\\Otvet:\boxed{-3,01}$