Question

2 и 3 помогите срочно​

Answer 1

2)

$\displaystyle \bigg(\frac{n^{-4}}{4m^{-5}} \bigg)^{-2}\times6n^6m^2=\\\\=\frac{n^8}{16m^{10}} \times6n^6m^2=\frac{96n^{14}}{m^8}$

3)

$\displaystyle\frac{5^0\times25^{-7}}{125^{-6}\times5^1} =\frac{5^0\times5^{-14}}{5^{-18}\times5^1} =5^{0+(-14)-(-18)-1}=5^3=125$