Question

ПОМОГИТЕ СРОЧНО САМОСТОЯТЕЛЬНАЯ РАБОТА, ДАЮ 100 БАЛЛОВ, ПЖ!!!!!!!!!!!!!!!!!!! ​

Answer 1

Ответ:

Объяснение:

$1. 1) -5<x<1;$

$-5*7<x*7<1*7$

$-35<7x<7;$

$2) -5*\frac{1}{3}<x*\frac{1}{3}<1*\frac{1}{3};$

$-\frac{5}{3}<\frac{x}{3}<\frac{1}{3};$

$3) -5+3<x+3<1+3;$

$-2<x+3<4;$

$4) -5-8<x-8<1-8;$

$-13<x-8<-7;$

$5) -5*(-1)>x*(-1)>1*(-1);$

$5>-x>-1;$

$2. 2,4<\sqrt{6}<2,5;$

$1) 9,6<4\sqrt{6}<10;$

$2) -12\sqrt{6}>-30>-12,5\sqrt{6};$

$3) 9,4-\sqrt{6}<7<9,5-\sqrt{6};$

$4) 0,8*(7-\sqrt{6})<\frac{7\sqrt{6}}{3}-2<\frac{2,5*(7-\sqrt{6})}{3};$

$5,6-0,8\sqrt{6}<\frac{7\sqrt{6}}{3}-2<\frac{2,5*(7-\sqrt{6})}{3};$

$3. 2<x<7;$

$\frac{2}{1}<\frac{x}{1}<\frac{7}{1};$

$\frac{1}{2}>\frac{1}{x}>\frac{1}{7};$

$4. 3<x<8 ; 2<y<7;$

$1) 5<x+y<15;$

$2) \frac{3}{2}<\frac{x}{y}<\frac{8}{7};$

$3) \frac{12}{15}<\frac{6y}{5x}<\frac{42}{40};$

$\frac{4}{5}<\frac{6y}{5x}<\frac{21}{20};$

$5. 12<x<20;$

$P: 48<4x<80;$

$S: 144<x^{2}<400;$