Question

ДАМ 50 БАЛЛОВ!!! НЕ СПАМЬТЕ И НЕ ОТВЕЧАЙТЕ НАУГАД АТО ЗАБАНЮ

Answer 1

$1)\ \ \dfrac{16k-4}{6-16k}+\dfrac{\star }{6-16k}=1\\\\\\\dfrac{\star }{6-16k}=1-\dfrac{16k-4}{6-16k}\ \ ,\ \ \ \dfrac{\star }{6-16k}=\dfrac{6-16k-16k+4}{6-16k}\ \ ,\\\\\\\dfrac{\star }{6-16k}=\dfrac{10-32k}{6-16k}\ \ ,\ \ \ \ \ \boxed {\ \star =10-32k\ }$

$2)\ \ t=8\ \ ,\ \ \dfrac{t^2+t+1}{t^3-27}-\dfrac{2t+8}{27-t^3}=\dfrac{t^2+t+1}{(t-3)(t^2+3t+9)}+\dfrac{2t+8}{(t-3)(t^2+3t+9)}=\\\\\\=\dfrac{t^2+3t+9}{(t-3)(t^2+3t+9)}=\dfrac{1}{t-3}=\dfrac{1}{8-3}=\dfrac{1}{5}$