Question

пожалуеста помогите​

Answer 1

Ответ:

$1. \sqrt{9a-4b} =\sqrt{9*16-4*11} =\sqrt{100} =10\\2. \sqrt{0,1x-y^2} =\sqrt{0,1*5-(0,1)^2} =\sqrt{0,49} =0,7\\3. \sqrt{10a+11b} =\sqrt{10*39+11*(-6)} =\sqrt{324} =18\\4.\sqrt{x^3-y^2}=\sqrt{10^3-(-30)^2} =\sqrt{100} =10\\5. \sqrt{\frac{2a}{b} } =\sqrt\frac{2*9}{32}=\sqrt{\frac{9}{16} }=\frac{3}{4} =0,75\\ 6. \sqrt{\frac{x}{y} }-\sqrt{\frac{y}{x} } =\sqrt{\frac{3}{243} }-\sqrt{\frac{243}{3} } =\sqrt{\frac{1}{81} }-\sqrt{81 } =\frac{1}{9} -9=-8\frac{8}{9}$

$7. \sqrt{(\frac{a}{b})^2-\frac{3}{b} } =\sqrt{(\frac{-4}{5})^2-\frac{3}{5} } =\sqrt{\frac{1}{25} } =\sqrt{0,04} =0,2\\8. \sqrt{8x^2-y^2} =\sqrt{8*(-\frac{1}{6})^2-(-\frac{1}{3})^2 } =\sqrt{\frac{1}{9} } =\frac{1}{3}$