Question

можете решить эти два неравенства? дам 20 б)))​

Answer 1

$1)3,125+x\leq 5,125-4^{-1}x \\\\3,125+x\leq 5,125-\frac{1}{4}x\\\\3,125+x\leq 5,125-0,25x\\\\x+0,25x\leq5,125-3,125\\\\1,25x\leq 2\\\\x\leq 1,6$

$2)12,5x-5,125<2^{-3} -4^{-1}x \\\\12,5x-5,125<\frac{1}{2^{3}}-\frac{1}{4}x\\\\12,5x-5,125<\frac{1}{8}-\frac{1}{4}x\\\\12,5x-5,125<0,125-0,25x\\\\12,5x+0,25x<0,125+5,125\\\\12,75x<5,25\\\\x<\frac{21}{51}$