Question

Розкрити дужки
1. 5(х+4)+3(2-х)
2. 7х-2(х-1)+4х
3. 4(5-х)-(2х+3)+7

Answer 1

1. 5(x+4)+3(2-х)=5х+20+6-3х=2х+26=х+13

2. 7х-2(х-1)+4х=7х-2х+2+4х=9х+2

3. 4(5-х)-(2х+3)+7=20-4х-2х-3+7=-6х+24=-х+4