Question

Люди прошу помогите, дам 60 баллов...

Answer 1

Ответ:

Объяснение:

а) =$\frac{6x^{2} *10y^{3} }{5y*3x} =2x2y^{2}$

б)=$\frac{8c*7d}{21d^{2}*6c^{2} } =\frac{4}{9dc}$

в)=$\frac{12p^{2}*35d^{2} }{7d^{4}*6p^{3} } =\frac{10}{d^{2} p }$

г)=$\frac{-9y^{2}16x }{20x^{3}y^{5} } =\frac{-36}{5x^{2}y^{3} }$

д)=$-\frac{3ab*10x^{2}y}{4xy*21a^{2}b } =-\frac{5x}{14a}$

е)= $\frac{18a^{2}b^{2}*5c^{2} d^{4} }{5cd*9ab^{3} } =\frac{2acd^{3} }{b }$

Answer 2

а) $\frac{6x^{2} }{5y} : \frac{3x}{10y^{3} } = \frac{6x^{2} }{5y} * \frac{10y^{3} }{3x} = 2x * 2y^{2} = 4xy^{2}$

б) $\frac{8c}{21d^{2} } : \frac{6c^{2} }{7d} = \frac{8c}{21d^{2} } * \frac{7d}{6c^{2} } = \frac{4}{3d} * \frac{1}{3c} = \frac{4}{9cd}$

в) $\frac{12p^{2} }{7d^{4} } : \frac{6p^{3} }{35d^{2} } = \frac{12p^{2} }{7d^{4} } * \frac{35d^{2} }{6p^{3} } = \frac{2}{d^{2} } * \frac{5}{p} = \frac{10}{d^{2} p}$

г) $-\frac{9y^{2} }{20x^{3} } : \frac{y^{5} }{16x} = -\frac{9y^{2} }{20x^{3} } * \frac{16x}{y^{5} } = -\frac{9}{5x^{2} } * \frac{4}{y^{3} } = -\frac{36}{5x^{2}y^{3} }$

д) $\frac{3ab}{4xy} : (-\frac{21a^{2}b }{10x^{2}y }) = -\frac{3ab}{4xy} * \frac{10x^{2}y }{21a^{2}b } = -\frac{1}{2} * \frac{5x}{7a} = -\frac{5x}{14a}$

е) $-\frac{18a^{2}b^{2} }{5cd} : (-\frac{9ab^{3} }{5c^{2}d^{2} }) = \frac{18a^{2}b^{2} }{5cd} * \frac{5c^{2}d^{2} }{9ab^{3} } = 2a * \frac{cd}{b} = \frac{2acd}{b}$