Question

Решите д,ж, з.
Задание: Извлеките корень

Answer 1

$1)\ \ a<0\ ,\ \ \ \sqrt{(6a)^2}=|\underbrace {6a}_{<0}|=-6a\\\\\\2)\ \ b<0\ ,\ \ \sqrt{2,56\, b^{10}}=1,6|\underbrace {b^5}_{<0}|=-1,6\, b^5\\\\\\3)\ \ xy>0\ \ \Rightarrow \ \ \ \left \{ {{x>0} \atop {y>0}} \right. \ \ ili\ \ \ \left \{ {{x<0} \atop {y<0}} \right. \\\\\\\sqrt{\dfrac{441\, x^2}{y^6}}=\dfrac{21\, |\, x\, |}{|\, y^3\, |}=\dfrac{21\, x}{y^3}$