Question

Найдите область определения функции

Answer 1

$y = \frac{ \frac{1}{x-1}-\frac{1}{x+1}}{\frac{1}{x-1}-\frac{1}{x+1}}$

$y = \frac{\frac{\frac{\frac{\frac{(x+1)-(x-1)}{(x-1)(x+1)}}}\((x+1)+(x-1)}{}}{(x-1)(x+1)}$

$y = \frac{(x+1)-(x+1)}{(x+1)+(x-1)}$

ОДЗ:

$(x+1)+(x-1)\neq 0$

$2x\neq 0$

$x\neq 0$

$D(y) = x$ ∈ (-∞; - 1) ∪ ( 1; +∞)