Question

Решите неравенство:(5y-6)(3y+5)(y-3)(y+1)≤0​

Answer 1

Ответ:

$(5y-6)(3y+5)(y-3)(y+1)\leq 0$

Корни уравнения:

$(5y-6)(3y+5)(y-3)(y+1)=0\\y_1=-1\frac{2}{3} ; y_2=-1; y_3=1,2; y_4=3$

Ответ: у ∈ [$-1\frac{2}{3}$; -1] ∪ [1,2]

или

$-1\frac{2}{3} \leq y \leq -1; 1,2\leq y\leq 3$