Question

1) 2у3 - 8у   2)0,16у - у3    

Answer 1

2y(y^2-4) = 2y(y-2)(y+2)
y(0.16 -y^2) = y(0.4 -y)(0.4+y)

Answer 2

1) $2y( y^{2} -4)=$ 2y(y-2)(y+2)
2) $y(0.16- y^{2} )$= y(0.4-y)(0.4+y)