Предмет: Химия, автор: snezhannaavdeeva

Формула глюкозы - C6H12O6 формула сахаров - С12 Н22 О11. В каком веществе массовая доля кислорода больше?

Ответы

Автор ответа: limonite2004
0

Ответ:

В глюкозе

Объяснение:

w(O) = M(O) * N(O) / M(C6H12O6) = 16*6/ 160 = 0.6;

w1(O) = M(O) * N(O) /M(C12H22O11) = 16 * 11/ 342 = 0.515;

w1 > w2

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