Question

АЛГЕБРА 8 КЛАСС СРОЧНО!!! ПЖ ПОМОГИТЕ!!!

Answer 1

Ответ:

Объяснение:

1.

1)6b/18a =b/3a

$\frac{6b}{18a}=\frac{b}{3a}$

2)18abc^2/3a^2b^2c=6c/ab

$\frac{18abc^{2}}{3a^{2}b^{2}c}=\frac{6c}{ab}$

2.

1) 6/7x^2y = 7x^10y^4/42x^8y^3

$\frac{6}{7x^{2}y}=\frac{7x^{10}y^{4}}}{42x^{8}y^{3}}$

2) 3/(a-7)=6/2(a-7)=6/2a-14

$\frac{3}{a-7}=\frac{6}{2(a-7)]=\frac{6}{2a-14}$

3.

1) a^4-a^6)/a^9-a^11)=a^4(1-a^2)/a^9(1-a^3)= =a^4(1-a)(1+a)/ (1-a)(1+a+a^2)=a^4(1+a)/(1+a+a^2)

2) (x^2-49)/(2x+14)=(x-7)(x+7)/2(x+7)=(x-7)/2

[tex}\frac{x^{2}-49}{2x+14)}=\frac{(x-7)(x+7)}{2(x+7)}=\frac{x-7}{2}[/tex]

3)(6x^2-3x)/(4-8x)=3x(2x-1)/(4(1-2x)=-3x(2x-1)/4(1-2x)=-3x(1-2x)/-4(1-2x)=3x/4

4)(x^2-81)/(27x+3x^2)=(x-9)(x+9)/3x(9+x)=(x-9)/3x

$\frac{x^{2}-81}{27x+3x^{2}}=\frac{x-9)(x+9)}{3x(9+x)}=\frac{x-9}{3x}$