Question

Помогите решить номер 15(1-2)

Answer 1

$1)f(x)=0,5x^{2} -3x-2\\\\0,5x^{2}-3x-2=0|*2\\\\x^{2}-6x-4=0\\\\D=(-6)^{2}-4*(-4)=36+16=52=(2\sqrt{13})^{2}$

$x_{1} =\frac{6-2\sqrt{13}}{2}=3-\sqrt{13}\\\\x_{2} =\frac{6+2\sqrt{13}}{2}=3+\sqrt{13}$

$2)f(x)=\sqrt{x+2}\\\\\sqrt{x+2}=0\\\\x+2=0\\\\x=-2$