Question

Помогите пожалуйста. Дам 25 балов Номер 41

Answer 1

$\dfrac{6}{b-4}=\dfrac{6\cdot 5}{5\cdot (b-4)}=\dfrac{30}{5b-20}\\\\\\\dfrac{6}{b-4}=\dfrac{6\cdot (-3)}{-3\cdot (b-4)}=\dfrac{-18}{12-3b}\\\\\\\dfrac{6}{b-4}=\dfrac{6\cdot b}{b\cdot (b-4)}=\dfrac{6b}{b^2-4b}\\\\\\\dfrac{6}{b-4}=\dfrac{6\cdot (b+4)}{(b-4)\cdot (b+4)}=\dfrac{6\, (b+4)}{b^2-16}$