Предмет: Геометрия, автор: annabigun2005

Площа прямокутника дорівнює 54 см². Знайдіть його сторони якщо одна на 3 см менша від іншої

Ответы

Автор ответа: Аноним

7

меньшая х. большая (х+3)

х*(х+3)=54

х²+3х-54=0

По Виету х=-9; ∅,х=6, значит. одна сторона 6см. а ей смежная 3+6=9/см/

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