Question

Решите систему неравенств.

Answer 1

$\left\{\begin{array}{l}3(2-3p)-2(3-2p)>p\\6<p^2-p(p-8)\end{array}\right\ \ \left\{\begin{array}{l}6-9p-6+4p>p\\p^2-p^2+8p>6\end{array}\right\ \ \left\{\begin{array}{l}-6p>0\\8p>6\end{array}\right\\\\\\\left\{\begin{array}{ccc}p<0\\p>\dfrac{3}{4}\end{array}\right\ \ \ \Rightarrow \ \ \ \ p\in \varnothing$