Question

(2y-c)^2+(y+2c)^2 при c=1,2и y=-1,4 решите пжж!!!

Answer 1

(2у-с)²+(у+2с)² = 4у²-4ус+с²+у²+4ус+4с² = 5у²+5с²

5у²+5с² = 5(у²+с²) = 5((-1.4)²+1.2²) = 5(1.96+1.44) = 5×3.4 = 17