Question

Найдите производную ф-ии: а) y=sin(3x-9); б) y=cos(П/3 - 4x).​

Answer 1

у' = sin(3x-9)' = sinu' × (3x-9)' = cosu × 3 = 3cos(3x-9)

y' = cos(π/3-4x)' = cosu' × (π/3-4x)' = -sinu × (-4) = -4sin(4x-π/3) = 4cos(4x+π/6)