Предмет: Алгебра, автор: adskiymatematik

помагите решить
логарифм ​

Приложения:

Ответы

Автор ответа: kedrovmisha00
2

Ответ:

x=\sqrt{10}

Объяснение:

По свойствам логарифма x^{lg9}=9^{lgx}, значит

x^{lg9}+9^{lgx}=2x^{lg9}=6\\x^{lg9}=3\\log_3x^{lg9}=log_33\\lg9*log_3x=1\\log_3x=\frac{1}{lg9}=log_910=\frac{1}{2}log_310=log_3\sqrt{10}\\x=\sqrt{10}


adskiymatematik: если не трудно откуда вы берете log3
kedrovmisha00: сам выбираю, просто хочу избавиться от степени, поэтому логарифмирую, основание логарифма выбираю сам
adskiymatematik: понятно
adskiymatematik: спасибо
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