Question

2) (b¹⁶)⁴: (b³)²⁰
3) (b⁹)¹²: (b¹⁰)¹⁰
5) (b³)⁷*· (b⁵)⁵
6) (b⁷)⁶: (b⁸)⁵​

Answer 1

Ответ:

2) $b^{16*4}:b^{3*20}=b^{64-60}=b^4$

3)$b^{9*12}:b^{10*10}=b{108-100}=b^8$

3) $b^{3*7}*b^{5*5}=b^{21+25}=b^{46}$

$4)b^{7*6}:b^{8*5}=b^{42-40}=b^2$

Объяснение: