Question

(x - 8)^2 - (x - 4)(x + 4) = 0

Answer 1

Ответ:

${(x - 8)}^{2} - (x - 4)(x + 4) = 0 \\ {x}^{2} - 16x + 64 - {x }^{2} + 16 = 0 \\ - 16x = - 16 - 64 \\ - 16x = - 80 \\ x = 5$