Question

Розв'яжіть систему рівнянь.
(х+3):2-(у-2):3=2
(х-1):4+(у+1):3=4​

Answer 1

$\left \{ {{\frac{x+3}{2} -\frac{y-2}{3} =2} \atop {\frac{x-1}{4}+\frac{y+1}{3}=4}} \right.\\\\\left \{ {{\frac{x+3}{2}*6 -\frac{y-2}{3}*6 =2*6} \atop {\frac{x-1}{4}*12+\frac{y+1}{3}*12=4*12}} \right.\\\\\left \{ {{3(x+3)-2(y-2)=12} \atop {3(x-1)+4(y+1)=48}} \right.\\\\\left \{ {{3x+9-2y+4=12} \atop {3x-3+4y+4=48}} \right.\\\\-\left \{ {{3x-2y=-1} \atop {3x+4y=47}} \right.\\ -------\\-6y=-48\\\\y=8\\\\3x=2y-1=2*8-1=15\\\\x=5\\\\Otvet:\boxed{(5;8)}$