Question

Помогите решить! 7(3m-1)+2=
14m^2-7m^2=
(4^3)^2*4^2=
4^3*4^7=

Answer 1

$7(3m-1)+2=21m-7+2=21m-5$

$14m^2-7m^2=7m^2$

$(4^3)^2*4^2=4^6*4^2=4^{6+2}=4^8=65 '536$

$4^3*4^7=4^{3+7}=4^{10}=1 '048' 576$