Question

решите систему уравнений ​

Answer 1

$\left \{ {{u-v=0} \atop {5u^2+2v=3}} \right. \\u=v\\5v^2+2v=3\\5v^2+2v-3=0\\D=4+4*5*3=64=8^2\\v_1=\frac{-2+8}{10}=0.6\\v_2=\frac{-2-8}{10}=-1\\u_1=0.6\\u_2=-1$

Ответ: (0.6;0.6), (-1;-1)