Question

9 класс не сложно помогите

Answer 1

$(4a-2)^{2} =4^{2}a^{2}-2*4a*2+2^{2} =16a^{2}-16a+4\\ (\frac{1}{2} -2x)^{2} =\frac{1}{2} ^{2}-2*2*\frac{1}{2}+2^{2} =\frac{1}{4}-2x+4x^{2} =0.25-2x+4x^{2} \\(0.1+x)^{2} =0.1^{2}+2*0.1*x+x^{2} =0.01+0.2x+x^{2} \\(-5+2x)^{2} =-5^{2}+2*(-5)*2x+2^{2}x^{2} =25+20x+x^{2} \\(3x-0.2)^{2} =3^{2}x^{2}-2*0.2*3x+0.2^{2} =9x^{2}-1.2x+0.04\\(3x-y)^{2} =3^{2}x^{2}-2*y*3x+y^{2} =9x^{2}-6xy+y^{2} \\(10-3x)^{2} =10^{2}-2*10*3x+3^{2}x^{2} =100-60x+9x^{2} \\(0.5x+1)^{2}=0.5^{2}x^{2}+2*0.5x*1+1^{2} =0.25+x+1$