Question

$6x ^{2} - 13x - 15 = 0$
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Answer 1

$\displaystyle 6x^2-13x-15=0\;\;\;\;\;\boxed{a=6\;\;\;\;b=-13\;\;\;\;c=-15}\\\\D=(-13)^2-4*6*(-15)=169+360=\sqrt{529}=23^2 \\\\x_1=\frac{-(-13)-\sqrt{529} }{2*6} =\frac{13-23}{2*6} =\frac{-10}{2*6} =\frac{-5}{6} =-\frac{5}{6} \\\\x_2=\frac{-(-13)+\sqrt{529} }{2*6} =\frac{13+23}{2*6} =\frac{36}{2*6} =\frac{18}{6} =3\\\\\\ \boxed{x_1=-\frac{5}{6} \;\;\;\;\;x_2=3}$